17x^2-4x-85=0

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Solution for 17x^2-4x-85=0 equation:



17x^2-4x-85=0
a = 17; b = -4; c = -85;
Δ = b2-4ac
Δ = -42-4·17·(-85)
Δ = 5796
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{5796}=\sqrt{36*161}=\sqrt{36}*\sqrt{161}=6\sqrt{161}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-6\sqrt{161}}{2*17}=\frac{4-6\sqrt{161}}{34} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+6\sqrt{161}}{2*17}=\frac{4+6\sqrt{161}}{34} $

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